The tens place digit of a two- digit number is twice the digit of unit place digit. The number obtained by interchanging the digits diminished the original number by 36. Find the number.
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face value of the digit at the tens place
2x
place value=2x×10=20x
face value of digit at the units place=x
place value=x×1=x
original no.=20x+x=21x
if the digits are interchanged
place value of digit at tens place=x×10=10x
place value of digit at units place=2x×1=2x
new no.=10x+2x=12x
difference Between them
=21x-12x=36
=9x=36
=x=36/9=4
the no is=21x=21×4=84
please mark me as brainliest
2x
place value=2x×10=20x
face value of digit at the units place=x
place value=x×1=x
original no.=20x+x=21x
if the digits are interchanged
place value of digit at tens place=x×10=10x
place value of digit at units place=2x×1=2x
new no.=10x+2x=12x
difference Between them
=21x-12x=36
=9x=36
=x=36/9=4
the no is=21x=21×4=84
please mark me as brainliest
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