Question

The tenth term of a arithmetic sequence is 82 with a common difference 8.which term is 250?​

Answer 1

Step-by-step explanation:

tenth term is a^n=a+(n-1)d

82=a+9×8

82=a+72

a=10

then, now we have the valued of

a=10,d=8,a^n=250,n=?

250=10+(n-1)8

250=10+8n-8

250-2=8n

248/8=n

n=31

Answer 2

31st term

Step-by-step explanation:

QUESTION :-

The 10th term of a Arithmetic sequence is 82 with a common difference 8. which term is 250 ?

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SOLUTION :-

Formula related to A.P., we will use

$a_{n} = a + (n - 1)d$

here,

• n = nth term of A.P.
• a = 1st term of A.P.
• d = common difference

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Now,

• 10th term of A.P. is 82, common difference is 8.

putting the value in formula,

10th term = a + (10-1)8 = 82

=> a + (9)8 = 82

=> a + 72 = 82

=> a = 82-72

=> a = 10

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• which term of A.P. is 250.

Let us consider 250 as nth term, so,

nth term = a + (n - 1)d = 250

=> 10 + (n - 1)8 = 250

=> (n - 1)8 = 250 - 10

=> 8n - 8 = 240

=> 8n = 240+ 8

=> 8n = 248

=> n = 248/8

=> n = 31

Hence, 250 is 31st term of this A.P.

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Hope it helps.

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