the tenth term of the sequence √3√12√27........ is
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Answer:
10√3
Step-by-step explanation:
Given,
A.P = √3, √12, √27, ........
a = √3
d = √12 - √3
= 2√3 - √3
d = √3
10th term is t10.
t10 = a + 9d
= √3 + 9√3
t10 = 10√3
Therefore, the 10th term ( t10 ) is 10√3.
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