Question

the the opposite angles of a parallelogram are (3x-2)⁰ and (x+48)⁰ find the measure of each angle of the parallelogram​

Answer 1

Answer:

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Step-by-step explanation:

Let four angles of given parallelogram taken in order be ∠A,∠B,∠Cand∠D respectively

Here opposite angles given ∠A=(3x−2)and∠C=(x+48)

We know that opposite angles of a parallelogram are equal

∴3x−2=x+48

2x=50

x=25

∴3x−2=73°

∠A=∠C=73°

Also we know that sum of two adjacent angles of a parallelogram is 180

∴∠A+∠B=180°

73°+∠B=180°

∠B=107°=∠D (Opposite angles are equal)

∴ All four angles of given parallelogram are 73°,107°,73°,107°

Answer 2

Step-by-step explanation:

Aloha !

Given,

Angles of parallelogram = (3x-2°) and (X+48°)

Total sum of parallelogram= 360°

(3X-2°)+(X+48°)=360°

3X-2°+X+48°=360°

4X+46°=360°

X+46°=360°÷4

X+46°=90°

X=90°-46°

X=44°.

=> (3x-2)

= 3×44-2

= 132-2

=130

=> x+48

=44+48

= 92

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