Question

The theoretical yield of zinc oxide in a reaction is 486 g. What is the percent yield of 399 g is produced

Answer 1

Answer:

89.7% yield

Explanation:

ZnO + H2O → Zn(OH)2  [balanced as written]

(3.16 g H2O) / (18.01532 g H2O/mol) x (1 mol Zn(OH)2 / 1 mol H2O) x  

(99.3947 g Zn(OH)2/mol) = 17.4 g Zn(OH)2 in theory

(15.6 g) / (17.4 g) = 0.897 = 89.7% yield

Answer 2

Given - Theoretical yield of zinc oxide : 486 gram

Actual yield of zinc oxide : 399 gram

Find - Percent yield of zinc oxide.

Solution - Percent yield can be calculated by the formula : Actual yield/ Theoretical yield * 100.

Keeping the provided values in equation-

Percent yield = 399/486*100

Percent yield = 82.1%

Hence, the percent yield of zinc oxide from the given data is 82.1%.