Question

the thermal conductivity of steel is 16.5 Btu/(h) (ft) (°F). What is the value of the thermal conductivity in W/(m) (°C)?​

Answer 1

Answer:

Calculate the R-value by taking the reciprocal of the conductivity C to get R = 1/3.93 = 0.254 kelvin-meter^2/watt. You can also calculate the R-value directly as R = L/K = 0.305/1.2 = 0.254 kelvin-meter^2/watt.

Explanation:

Calculate the R-value by taking the reciprocal of the conductivity C to get R = 1/3.93 = 0.254 kelvin-meter^2/watt. You can also calculate the R-value directly as R = L/K = 0.305/1.2 = 0.254 kelvin-meter^2/watt. Notice that the thicker the material is, the higher the R-value is.