the thickness of a hollow metal cylinder is 2 cm 70 cm long with outer radius of 14 cm find the volume of metals required to make a the cylinder assuming it is open at both end also find its weight the metals with 8 gram per centimetre cube
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volume of outer cylinder =
![\pi {r}^{2} h \\ \frac{22}{7} \times 14 \times 14 \times 70 \pi {r}^{2} h \\ \frac{22}{7} \times 14 \times 14 \times 70](https://tex.z-dn.net/?f=%5Cpi++%7Br%7D%5E%7B2%7D+h+%5C%5C++%5Cfrac%7B22%7D%7B7%7D++%5Ctimes+14+%5Ctimes+14+%5Ctimes+70)
=43120
volume of inner cylinder =
![\frac{22}{7} \times 12 \times 12 \times 70 \frac{22}{7} \times 12 \times 12 \times 70](https://tex.z-dn.net/?f=+%5Cfrac%7B22%7D%7B7%7D++%5Ctimes+12+%5Ctimes+12+%5Ctimes+70)
=31680
volume of metal used in cylinder =
volume of outer cylinder =
=43120
volume of inner cylinder =
=31680
volume of metal used in cylinder =
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