Question

The thickness of a hollow metalic cylinder is 2cm.It is 35 cm long & its inner radius is 12 cm find the volume of metal required to make the cylinder assuming it is open at either end

Answer 1

Answer:

5720cm^3

Step-by-step explanation:

inner radius of cylinder =12cm

outer radius of cylinder =inner radius +thickness of cylinder

outer radius =(12+2)cm=14cm

height of cylinder =35cm

Volume of metal required to make the cylinder =outer volume of cylinder -inner volume of cylinder

=πR^2h-πr^2h

=πh(R^2-r^2)

=22/7*35(14^2-12^2)

=110(196-144)

=110*52

=5720cm^3

therefore, volume of metal required for making hollow metalic cylinder =5720cm^3

Answer 2

Answer:

$\huge \bold{5720 {cm}^{3} }$

Step-by-step explanation:

$\red{ \sf{ \underline{ \purple{ \underline{ \blue{given}}}}}}$

thickness of hollow cylinder is 2 cm

length=35cm

Inner radius=12cm

outer radius=12+2=14cm

$\huge \orange{ \fbox{ \fbox{ \red{ \mathfrak{solution}}}}}$

volume volume of wood required to make the cylinder = volume of whole cylinder - volume of hollow cylinder.

$\pi \times {r}^{2} \times h - \pi \times {r}^{2} \times h$

$= \: \: \pi( {r}^{2} - {r}^{2} )h$

$= \frac{22}{7} ( {14}^{2} - {12}^{2} )35$

$= \frac{22}{7} (196 - 144)35$

$= \frac{22}{ \cancel7} \times 52 \times \cancel35$

$= 22 \times 52 \times 5$

$= 5720 {cm}^{3}$

$\bf{hope \: this \: helps \: you }$