Question

the thickness of a hollow metallic cylinder is 2 cm It is 35 cm long and its inner radius is 12 cm find the volume of a material required to make the cylinder resuming it is open at the other end

Answer 1

SOLUTION :

The thickness of the hollow metallic cylinder = 2cm

The length of the hollow metallic cylinder = 35 cm

The inner radius (r) of the hollow cylinder = 12 cm

The outer radius (R) of the hollow cylinder = inner radius + thickness

                                                                       = 12 + 2

                                                                       = 14 cm

Now,

To be found :-

The volume of the hollow metallic cylinder

Volume = πh( $\ {R}^{2}$ -  $\ {r}^{2}$ )

            = $\frac{22}{7} \times 35$ ( $\ { (14)}^{2}$ -  $\ { (12)}^{2}$ )

             = $22 \times 5$ ( $192$ -  $144$ )

             = $\boxed{\bold{5720 \: cm \: square}}$

Hence,

The volume of the hollow metallic pipe is 5720 cm square.