Question

the thickness of a hollow metallic cylinder is 2 cm It is 35 cm long and its inner radius is 12 cm find the volume of metal required to make the cylinder asuming it is open at either end

Answer 1

Answer:

5720 cm^3

Step-by-step explanation:

are of metal used = outer area-inner area

                             =  $\pi h (R^2-r^2)$

                              = 22/7 x 35 x (14^2 - 12^2)  

                               =22 x 5 x (196-144)

                               =110 x 52

                                =5720 cm^3

Answer 2

Answer:

$\huge \bold{5720 {cm}^{3} }$

Step-by-step explanation:

$\blue{ \sf{ \underline{ \pink{ \underline{ \purple{given}}}}}}$

thickness of hollow cylinder is 2 cm

length=35cm

Inner radius=12cm

outer radius=12+2=14cm

$\huge \orange{ \fbox{ \fbox{ \red{ \mathfrak{solution}}}}}$

volume volume of wood required to make the cylinder = volume of whole cylinder - volume of hollow cylinder.

$\pi \times {r}^{2} \times h - \pi \times {r}^{2} \times h$

$= \: \: \pi( {r}^{2} - {r}^{2} )h$

$= \frac{22}{7} ( {14}^{2} - {12}^{2} )35$

$= \frac{22}{7} (196 - 144)35$

$= \frac{22}{ \cancel7} \times 52 \times \cancel35$

$= 22 \times 52 \times 5$

$= 5720 {cm}^{3}$

$\bf{hope \: this \: helps \: you }$