Question

The thickness of a hollow metallic cylinder is 2 cm. It is 70 cm long with outer radius of 14 cm. Find the volume of

the metal used in making the cylinder, assuming that it is open at both the ends. Also find its weight if the metal

weighs 8 g per cm^3

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Answer 1

Answer: 91.52 kg

Step-by-step explanation:

Given : Thickness of cylinder =2 cm

            Length of cylinder (h) =70 cm

            Outer Radius (R) =14 cm

inner Radius(r)  = outer Radius - thickness

                           =14-2

                           =12 cm

Volume of hollow cylinder = $\pi h (R^{2} - r^{2})$

                                            = $\frac{22}{7}$ × 70× (14²-12²)

                                            = 22 × 10 × 52

                                            =11440 cm³

Weight of 1 cm³=8 gm

So weight of 11440 cm³=11440 x 8

                                      =91520 gm

(1 kg=1000 gm)  

∴ 91520/1000

=91.52 kg

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