Question

The thickness of a metallic tube is 1 cm and the inner diameter of the tube is 12 cm. Find the mass of 1 m long tube, if the density of the metal be 7.8 gm/cm^3​

Answer 1

Answer:

Inner radius,r=12/2=6cm

Inner radius,r=12/2=6cmthickness=1cm

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cm

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cm

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100286/7×100

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100286/7×100=28600/7

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100286/7×100=28600/7since,density=7.7gm/cm^3

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100286/7×100=28600/7since,density=7.7gm/cm^3also,weight=volume×density

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100286/7×100=28600/7since,density=7.7gm/cm^3also,weight=volume×densityweight=28600/7×7.7gm

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100286/7×100=28600/7since,density=7.7gm/cm^3also,weight=volume×densityweight=28600/7×7.7gm=31460gm

Inner radius,r=12/2=6cmthickness=1cmso,outer radius,R=6+1=7cmheight,h=1m=100cmvolume=pi×(R^2-r^2)×h=22/7×(7^2-6^2)×100=22/7×(49-36)×100=22/7×13×100286/7×100=28600/7since,density=7.7gm/cm^3also,weight=volume×densityweight=28600/7×7.7gm=31460gm or,31.46 kg

Step-by-step explanation:

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Answer 2

Given:

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• Thickness of the metal tube = 1 cm

• Inner diameter of the tube = 6 cm

• Inner radius of the tube = 6 cm

• Density of the metal = 7.8 gm/cm$^{3}$

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To find:

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Mass of 1 m long tube.

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Solution:

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Volume of the metal in the tube

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= π(R$^{2}$ – r$^{2}$)h

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= (7$^{2}$ – 6$^{2}$) × 100 cm$^{3}$

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= 22/7 × 13 × 100 cm$^{3}$

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We know that,

Mass = Volume × Density

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So, mass of the tube = 22/7 × 13 × 100 × 7.8 gm

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= 31868.57 gm

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$= \frac{31868.57}{1000} kg$

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= 31.86857 kg

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Hence, the mass of 1 m long tube, if the density of the metal be 7.8 gm/cm$^{3}$.