The thiosulfate ion (s2o32-) is oxidized by iodine as follows: 2s2o32-(aq) + i2(aq) → s4o62-(aq) + 2i-(aq) in a certain experiment, 5.46×10-3 mol/l of s2o32- is consumed in the first 11.0 seconds of the reaction. calculate the rate of consumption of s2o32-.
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The thiosulfate ion (S2O32-) is oxidized by iodine as follows: 2S2O32-(aq) + I2(aq) ?S4O62-(aq) ... The thiosulfate ion (S2O32-) is oxidized by iodine as follows: 2S2O32-(aq) + I2(aq) ? S4O62-(aq) + 2I-(aq).
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