Question

the third term of an A.P. is 8 and the 9th term exceeds 3 times the 3rd term by 2. Find the sum of its first 19 terms​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

DEAR HUMAN BEING,

= a3 = a + 2d

=   8 = a + 2d----------------------1

and,

= a9 = 3 * a3 + 2

  a + 8d = 3 * 8 + 2

=  a+8d=26...........................2

NOW, SUBTRACTING 2 - 1 ,

= a + 8d - a - 2d = 18

d=3

SUBSTITUTING D=3 IN 1 ,

= a + 2 * 3 = 8

= a = 2

NOW,

Sn = n\2(2a + ( n - 1 ) * d

S19 = 19\2 (4 + 54 )

S19 = 551.

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