The third term of an AP is 1/5 and the 5th term is 1/3. Show that the sum to 15 terms of the AP is 8.
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a+2d=1/5 - a+4d=1/3
=-2d=-2/15
=d=1/15
a=1/15
a15=1/15+14×1/15
a15=1
s15=n/2 (a+a15)
=15/2 (1/15+1)
=8
=-2d=-2/15
=d=1/15
a=1/15
a15=1/15+14×1/15
a15=1
s15=n/2 (a+a15)
=15/2 (1/15+1)
=8
sampadpaul50:
please can you show how the value of x"a" came
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