The third term of an AP is twice the first term. Prove that the 12th term of an AP is thrice the fourth term
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Step-by-step explanation:
Un = a + (n-1)d
a+2d = 2a → a = 2d
U12 = a+11d = 13d
U4 = a +3d = 5d
U12/U4 = 13/5 = 2.6 ≅ 3
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