Question

The thirteenth term of an A.P is two times its tenth term and the third term
is 6 more than two times its sixth term. Find the first three terms.

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Answer 1

here the answer

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Answer 2

Step-by-step explanation:   $T_{13} =2 T_{10} and T_{3} = 2 T_{6} + 6$   (given)

                                         a + 12d   = 2 ( a+ 9d)   and  a + 2d =2 (a+ 5d) +6

                                  from here  ⇒ a =  - 6d       and  a  =  -8d-6 solving these two ,we get  a  = 18  and  d  = -3  so first three terms are  a , a+ d , a + 2d

put a and  d ,we get      18 ,15 , 12