the three adjacent faces of a cube is x,y,z and its volume is
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Let the sides of the cube be a.
Given x, y and z are areas of three adjacent faces of the cuboid Hence x=a2, y=a2, z=a2
(x)(y)(z) = (a2)(a2(a2)
xyz= (a3)2 a3 = √xyz Thus the volume of cuboid, V= a3 = √xyz
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Given x, y and z are areas of three adjacent faces of the cuboid Hence x=a2, y=a2, z=a2
(x)(y)(z) = (a2)(a2(a2)
xyz= (a3)2 a3 = √xyz Thus the volume of cuboid, V= a3 = √xyz
hope its helpful...
thank you...
please mark my answer as brainliest....and follow me...
Answered by
0
Answer:
Let the 3 dimensions of the cuboid be l,b and h
So,
x=lb
y=bh
z=hl
multiplying above three equations,
xyz=lb×bh×hl
=l
2
b
2
h
2
As,
V=lbh
So,
V
2
=l
2
b
2
h
2
V
2
=xyz
Hence Proved
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