Question

the three angle of a triangle are in the ratio 4:5:6 find all the angles of the triangle

Answer 1

Let the measure of angles be (4x)°,(5x)°,(6x)°


We know​ that
Sum of all angles of triangle=180°

4x+5x+6x=180
15x=180
x=180\15
x=12


hence,
angles=(4x)°=(4×12)°=48°

Similarly
other angles=60°and72°

Answer 2

sum of all anglez of a ∆ is 180
so,
let 1st angle be 4x
". 2nd angle be 5x
and 3rd angle be 6x

Then,
4x+5x+6x=180
15x=180
x=12
Now,
1st angle =4×12=48°
2nd angle =5×12=60°
3rd angle = 6×12=72°.