The three angle of a triangle measure (2x-10°),(x+31°) and (5x+7°).Find the value of x and hence all the angles of a triangle.
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(2x-10)+(x-31)+(5x+7) = 180°
2x-10+x-31+5x+7=180°
2x+x+5x-10-31+7=180°
8x-44=180°
8x=180°+44
8x=324
x=324÷8
x=81/2
so,
(2x-10°)=2×81/2-10
= 71°
(x+31°)=81/2+31°
=143/2
(5x+7°)=5×81/2+7
=391/2
nokoo:
i dont know it is correct or not srry
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36
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