The three angles of a triangle are 11x-1,4x+15 and 20x-9.find the measure of all the angles of the triangle.with formula plz
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39
Answer :
We know that ,
Sum of Angles of a Triangle = 180
therefore ,
(11x-1) +(4x+15)+(20x-9)=180
or 11x-1+4x+15+20x-9 = 180
or 11x+4x+20x -1+15-9 =180
or 35x +5 =180
or 35x = 180 -5
or 35x =175
or x =175/35
or x =5
Therefore the angles of triangle are
11x -1 =11*5 -1 = 55 -1 = 54
4x+15 =4*5+15 =20+15 =35
20x-9 =20*5 - 9 =100 -9 =91
Therefore three angles of a triangle are 54,35 and 91.
Hope this helps you.
Thank You
Tawseef
We know that ,
Sum of Angles of a Triangle = 180
therefore ,
(11x-1) +(4x+15)+(20x-9)=180
or 11x-1+4x+15+20x-9 = 180
or 11x+4x+20x -1+15-9 =180
or 35x +5 =180
or 35x = 180 -5
or 35x =175
or x =175/35
or x =5
Therefore the angles of triangle are
11x -1 =11*5 -1 = 55 -1 = 54
4x+15 =4*5+15 =20+15 =35
20x-9 =20*5 - 9 =100 -9 =91
Therefore three angles of a triangle are 54,35 and 91.
Hope this helps you.
Thank You
Tawseef
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3
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