the three sides of a triangle are consecutive integers and their perimeter is 72 cm. Find the measure of each side of a triangle.
plz answer it fast and correctly because tomorrow is my test
Answers
✬ Sides = 23 , 24 , 25 cm ✬
Step-by-step explanation:
Given:
- Measure of three sides of a triangle are consecutive integers.
- Perimeter of triangle is 72 cm.
To Find:
- What is measure of each side of triangle ?
Solution: Let the first integer be x , second be x + 1 , third be x + 2. Therefore,
➟ First side = x cm
➟ Second side = (x + 1) cm
➟ Third sides = (x + 2) cm
As we know that
★ Perimeter of ∆ = Sum of all sides ★
A/q
- Perimeter is 72 cm
x + x + 1 + x + 2 = 72
3x + 3 = 72
3x = 72 – 3
3x = 69
x = 69/3
x = 23
Hence, Sides of triangle are
➭ First side = x = 23 cm
➭ Second side = x + 1 = 23 + 1 = 24 cm
➭ Third side = x + 2 = 23 + 2 = 25 cm
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★ Verification ★
=> 23 + 24 + 25 = 72
=> 47 + 25 = 72
=> 72 = 72
✨ The three sides of a triangle are consecutive integers and their perimeter is 72 cm. Find the measure of each side of a triangle.
✒ The measure of each side of triangle are 23 , 24 & 25 cm .
Given :-
- The measure of three sides of a triangle are consecutive integers.
- The Perimeter of triangle is 72 cm.
To Find :-
The measure of each side of triangle .
Calculation :-
Let the first integer be x , second be x + 1 , third be x + 2. {Given, the measure of three sides of a triangle are consecutive integers.}
▶ I side = x cm
▶ II side = (x + 1) cm
▶ III sides = (x + 2) cm
✏ The Perimeter of ∆ = ( a + b + c )
According to the question ,
⭐ The Perimeter of triangle is 72 cm.{Given}
⟿ x + (x + 1) + (x + 2) = 72
⟿ x + x + x + 1 + 2 = 72
⟿ 3x + 3 = 72
⟿ 3x = 72 – 3
⟿ 3x = 69
⟿ x = 69/3
⟿ x = 23
Therefore, The Sides of triangle are ,
I side => x = 23 cm
II side => (x + 1) = 23 + 1 = 24 cm
III side => (x + 2) = 23 + 2 = 25 cm
➡ So, the three sides of triangle are 23 , 24 & 25 cm .
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➩ ѵєяıƒıcαтıση
▶R.H.S
= 23 + 24 + 25
= 47 + 25
➡ 72
▶L.H.S
= 72
✳ The Perimeter of ∆ = ( a + b + c )
↗ 72 = 72
Hence, Verified ☑
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