Question

The three sides of sight angle triangle
x ,x+1 and 5
find the area
if largest side is 5​

Answer 1

Answer:

here

by pythagoreas theorem

{(x + 1)}^{2} + {x}^{2} = {5}^{2}(x+1)

2

+x

2

=5

2

opening

{(x + 1)}^{2} = {x}^{2} + 1 + 2x(x+1)

2

=x

2

+1+2x

therefore

{x}^{2} + 1 + 2x + {x}^{2} = 25x

2

+1+2x+x

2

=25

2 {x}^{2} + 2x = 242x

2

+2x=24

2( {x}^{2} + x) = 242(x

2

+x)=24

{x}^{2} + x = 12x

2

+x=12

{x}^{2} + x - 12 = 0x

2

+x−12=0

{x}^{2} + 4x - 3x - 12 = 0x

2

+4x−3x−12=0

x(x + 4) - 3(x + 4) = 0x(x+4)−3(x+4)=0

(x - 3)(x + 4) = 0(x−3)(x+4)=0

either x=3 or x=-4

but side cannot be negative therefore x=3

hence, other side =4

Area=1/2×4×3

=2×3

=

6 {cm}^{2}6cm

2

hence area =6sq cm

Step-by-step explanation:

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