Question

The three vertices of a parallelogram ABCD are A(3,-4) B(-1,-3) and C(-6,2). Find the coordinates of vertex D and find the area of ABCD.

Answer 1

find mid point O of A and C
x=(3-6)/2
-3/2
y=(-4+2)/2
-1
O=(-3/2,-1)
taking O as mid point find D
-3/2=(-1+x1)/2
x1=-2

-1=(-3+y1)/2
y1=1

D=-2,1

Answer 2

here is ur answer...