Question

The threshold energy of a metal is 4.12 * 10^14 sec^ -1 . Calculate kinetic energy of electron emitted when radiation of light having ν=1.05*10^15 sec^-1 hits the metal.

Answer 1

Answer:

The answer is 4. 2 * 10^-19 J

Explanation:

I have just used the photoelectric

equation to solve this check the picture

and h is the Plank's constant its value is 6.626*10^-34