Question

The time for a pendulum to swing, T s, is inversely proportional to the square root of the
acceleration due to gravity, gm/s. On Earth, g = 9.8m/s², but on the Moon, g = 1.9 m/s².
Find the time of swing on the Moon of a pendulum when the time that it takes to swing on
Earth is 2 s.​

Answer 1

Answer:

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Answer 2

LEARNING OBJECTIVES

By the end of this section, you will be able to:

• Measure acceleration due to gravity.

In the figure, a horizontal bar is drawn. A perpendicular dotted line from the middle of the bar, depicting the equilibrium of pendulum, is drawn downward. A string of length L is tied to the bar at the equilibrium point. A circular bob of mass m is tied to the end of the string which is at a distance s from the equilibrium. The string is at an angle of theta with the equilibrium at the bar. A red arrow showing the time T of the oscillation of the mob is shown along the string line toward the bar. An arrow from the bob toward the equilibrium shows its restoring force asm g sine theta. A perpendicular arrow from the bob toward the ground depicts its mass as W equals to mg, and this arrow is at an angle theta with downward direction of string.

Figure 1.

In Figure 1 we see that a simple pendulum has a small-diameter bob and a string that has a very small mass but is strong enough not to stretch appreciably. The linear displacement from equilibrium is s, the length of the arc. Also shown are the forces on the bob, which result in a net force of −mg sinθ toward the equilibrium position—that is, a restoring force.

Pendulums are in common usage. Some have crucial uses, such as in clocks; some are for fun, such as a child’s swing; and some are just there, such as the sinker on a fishing line. For small displacements, a pendulum is a simple harmonic oscillator. A simple pendulum is defined to have an object that has a small mass, also known as the pendulum bob, which is suspended from a light wire or string, such as shown in Figure 1. Exploring the simple pendulum a bit further, we can discover the conditions under which it performs simple harmonic motion, and we can derive an interesting expression for its period.

We begin by defining the displacement to be the arc length s. We see from Figure 1 that the net force on the bob is tangent to the arc and equals −mg sinθ. (The weight mg has components mg cosθ along the string and mg sinθ tangent to the arc.) Tension in the string exactly cancels the component mg cosθ parallel to the string. This leaves a net restoring force back toward the equilibrium position at θ = 0.