Physics, asked by perfect6494, 11 months ago

The time of oscillation T of a small drop of liquid depends on radius r, density ρ and surface tesnsion S. The relation between them is given by(a) T\ \alpha\ \sqrt{\frac{S}{\rho r^{3}}}(b) T\ \alpha\ \sqrt{\frac{\rho r^{3}}{S}}(c) T\ \alpha\ \sqrt{\frac{S^{2} r^{3}}{\rho}}(d) T\ \alpha\ \sqrt{\frac{\rho^{2} r^{3}}{S}}

Answers

Answered by nash49
0

The answer is option (a)

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