Question

The time period of a satellite in a circular orbit of radius r is t

Answer 1

By keeper’s law,

T2 ∝ R3

(T1 / T2) = (R1 / R2)3/2

Given,

R1 = R.

and

R2 = 4R (T1 / T2) = (R / 4R)3/2 = (1/8) (T1 / T2) = (1 / 8)

i.e. T2 = 8T1

given T1 = T

T1 = T hence T2 = 8T

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