Question

the time period of a source of sound is 0.6 seconds.how many times does it vibrate in 9 minutes?

Answer 1

Answer:

900

Explanation:

Since,

f= 1/T

f= 1/0.6

=10/6

Time given= 9×60 s

= 540s

No. of vibrations= frequency × time given

=(10/6)×540

= 900 Ans.

Please mark as brainliest.☺

Answer 2

900 times does it vibrate in 9 minutes.

Explanation:

Given,

The time period of a source of sound(T) = 0.6 seconds and

Total time = 9 minutes = 9 × 60 seconds = 540 seconds

To find, the number of vibration in 9 minutes = ?

We know that,

Frequency, f$=\dfrac{1}{Time period(T)}$

$=\dfrac{1}{0.6} s^{-1}$

$=\dfrac{10}{6} s^{-1}=\dfrac{5}{3} s^{-1}$

Number of vibrations = frequency × Total time

$=\dfrac{5}{3} s^{-1}\times 540s$

$=5 \times 180=900$

Hence, 900 times does it vibrate in 9 minutes.