Question

The time period of a source of sound is 0.6s .How many times does it vibrate in 9min?​

Answer 1

Answer: time period is the time taken for one oscillation.

54 into 6 times it will vibrate. that is 324 vibrations.

first, we have to convert 9 minutes into seconds...then multiply it with 0.6.

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Answer 2

The source of sound will vibrate 900 times.

Explanation:

Given that,

The time period of a source of sound is 0.6 s. We need to find the number of vibrations in 9 min or 540 seconds.The total number of oscillation per unit time is called its frequency. It is given by :

$f=\dfrac{n}{t}$

Since, $f=\dfrac{1}{T}$

Here, T = 0.6 s and t = 540 s

$\dfrac{1}{T}=\dfrac{n}{t}$

$n=\dfrac{t}{T}$

$n=\dfrac{540}{0.6}$

n = 900

So, the source of sound will vibrate 900 times. Hence, this is the required solution.

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