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Answer :-
ANGLE AOP = 65°
Step-by-step explanation:
angle PAQ = 50° [BY linear pair]
angle P = 90° (tangent is perpendicular from centre to a circle)
Though, By angle sum property,
Angle O = 180-90-25
ANGLE AOP = 65°
{we took 25 instead of 50 because angle O bisects angle A.
Thus dividing it in 2 equal parts.}
angle POQ = 130°
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