the time period of oscillation of a simple pendulum in an experiment is recorded as 2.56s, 2.62s, 2.70s, 2.58s, 2.45s respectively. Find the time period, mean absolute error and percentage error.
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Explanation:
A1=2.56
A2=2.62
A3=2.70
A4=2.58
A5=2.45
avg a=2.582
delta a=absolute error in the measurements are=(2.56-2.58)=-0.02
(2.62-2.62)=0
(2.70-2.62)=0.08
(2.58-2.62)=-0.04
(2.45-2.62)=-0.17
mean absolute errors=(-0.02+0+0.08-0.04-0.17)/5=-0.03
relative error=±0.03/2.58=±0.011
percentage error=1.16%
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