the time period of satellite of earth in a circular orbit of radius r is t. the period of another satellite of earth in a circular orbit of radius 4r is
ishu146:
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according to Kepler's law T is proportional to r^(3/2)
T1/T2= (r1/r2)^3/2
T2= 8 T1
Therfore answer is 8t
T1/T2= (r1/r2)^3/2
T2= 8 T1
Therfore answer is 8t
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