Question

the time period of simple pendulum of length L is measured in an elevator descending with an acceleration g/3 as.​

Answer 1

Explanation:

given length of pendulum is L and

The acceleration isadescending with g/3

then new acceleration = g-g/3

= 2g/3

then Time Period = 2π√(length)/(acceleration)

= 2π√L/(2g/3)

= 2π√(3L/2g)

Thats your Ans...

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