Question

The time period of the simple pendulum at a place are in the ratio 2:1.What will be the ratio of their length?​

Answer 1

Answer:

Explanation:

the ratio of length would be $\sqrt{2}:1$

as t ∝ $\sqrt{L}$  as of T=2π$\sqrt{L/g}$

Answer 2

Explanation:

Secondary School 

 

Physics 

 

5+3 pts

The time periods of two simple pendulums at a place are in ratio 2:1. what will be the ratio pf their length

by Bajaj1 17.03.2017

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Answers





Kokan6515

Ace

T=2π√[l/g]

we can se T² is directly proportional to length

so L1/L2=(T1/T2)²

T1/T2 is 2:1

so L1/L2=4/1

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Skyfall63

Ace

The ratio of their length is 4 : 1

Given:

The time period of two simple pendulum are in the ratio of 2 : 1  

Solution:

Time period of a simple pendulum is calculated by the formula,

T=

$2\pi \sqrt[lg]{?}$

Let us assume that the time period for first pendulum be T1 and for second pendulum be T2,

Thereby we have,





Dividing equation (1) and (2), we get,



On squaring both sides, we get,







Therefore, the length of the two simple pendulum be 4 : 1