Question

The time taken by the galvanic cell which operates almost ideally

Answer 1

Dear student,

Given:

Current = 10-16 A

Charge = 96548 C ( Charge on 1 mole of electrons )

Using the formula,

Charge(Q) = Current(A) x Time (T)

96548 C = 10-16 A x T

T = ( 96548 / 10-16)

T = 9.65 x 1020 sec

Answer 2

Answer:

9.65 ×10^20 sec

Explanation:

charge on 1 mole e-(Q) = 96500 C

I = 10^-16A

t= (?)

I=Q/t

t= Q/I

= 96500/ 10^-16

= 9.65 × 10^20 sec