Question

The time taken for a certain volume of gas to diffuse through a small hole was 2min .under similar conditions an equal volume of oxygen took 5.65 min to pass the molecular mass of gas is

Answer 1

Rate of diffusion of gases is inversely proportional to the square root of its MOLECULAR MASS

Rate1/rate2 = (M2/M1)1/2 = t2/t1

2nd gas is the oxygen gas and 1st is the other gas given. t is time taken for diffusion and M is the molecular masses of gases .

(32/M1)1/2 = 5.65/2

Squaring both sides:

32/M1 = 31.9225/4

M1 = (32 * 4 )/31.9225 = 4.0097

Therefore ,the molecular mass of the other gas is 4.0097

Answer 2

Answer:

the rate of difussion is inversly prop to square root of m and ans is 4 subscribe to assv vines please dekho mai ne tumhe ans bataya aur mujhe pata hai ki tum log exam mai cheating kar te ho aur ye and bhi dekhoge is liye mai kya bol ta hu subscribe to assv vines