The time taken for effusion of 32 mL of oxygen will be the same as the time taken for effusion under identical conditions of:
Answers
Given : The time taken for effusion of 32 mL of oxygen will be the same as the time taken for effusion under identical conditions of :
(A) 64 ml of H2
(B) 50 ml of N2
(C) 27.3 ml of CO2
(D) 22.62 ml of SO2
solution : according to Graham's law of effusion of gas
rate of effusion of a gas is inversely proportional to square root of its molecular weight. i.e., r ∝ 1/√M
for oxygen gas,
r ∝ 1/√(32)
⇒32/t = k/√(32) , where k is proportionality constant.
⇒kt = 32√(32) ≈ 181 ......(1)
let's check options,
(A) 64/t = k/√(2) ⇒kt = 64√2 = 90.5
(B) 50/t = k/√(28) ⇒kt = 50√28 = 264.57
(C) 27.3/t = k/√(44) ⇒kt = 27.3√(44) = 182
(D) 22.6/t = k/√(64) ⇒kt = 22.62√64 = 181
here we see option (D) is same as equation (1).
Therefore option (D) is correct choice.
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Answer:
d
Explanation:
Using Graham's law of diffusion :
r
gas
r
O
2
=
M
O
2
M
gas
V
64
=
32
64
or V=
2
64
=45.25 mL.
Hence, the correct option is D.