The time taken to stop a ball rolling with velocity u is reduced to half find the change in values of - 1 ) initial and final momenta 2) momentum change 3) rate of momentum change.
Answers
Answer:
Hey! mate.... Here is your Answer
Explanation:
Let a body of mass m and velocity v is brought to test in time t.
Initial momentum = mv
Final momentum = m× 0 = 0 ( as the ball is brought to test its velocity is zero)
Change in momentum = final momentum - initial momentum= 0 - mv
Time in which ball is brought to rest = t
Rate of change in momentum = - m v/t
Force F = Rate of change of momentum =- mv/t
Impulse = Force F × t = change in momentum = -mv
When the time in which the ball is brought to rest is halved, there is no change in,
Initial momentum, it remains m v
Final momentum, it remains zero
Change in momentum, it remains - m v.
The only change is in the rate of change of momentum, which is doubled when the time is halved. Though impulse (=change in momentum) does not change, the force required is doubled.
Hope it helps.....