The times for running a 5K for a local charity event are Normally distributed, with a mean time of 28 minutes and standard deviation of 5.4 minutes. Which time represents the 60th percentile?
Find the z-table here.
19.6 minutes
26.6 minutes
29.4 minutes
36.4 minutes
Answers
Given : The times for running a 5K for a local charity event are Normally distributed, with a mean time of 28 minutes and standard deviation of 5.4 minutes.
To Find : Which time represents the 60th percentile?
19.6 minutes
26.6 minutes
29.4 minutes
36.4 minutes
Solution:
time represents the 60th percentile
Means 60 % data = 0.6 below this
from z table , z score for this = 0.253
z score = ( Value - Mean ) / SD
=> 0.253 = ( Value - 28 ) /5.4
=> 1.3662 = Value - 28
=> Value = 29.3662
=> Value = 29.4
29.4 minutes represents the 60th percentile
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