the tip of seconds hand of a clock takes 60 seconds to move once on the circular dial of the clock if the radius of the dial of the clock be 10.5 CM calculate the speed of the tip of the second hand of the clock
Answers
Ans
radius of dial of clock=10.5CM
Circumference of clock=2πr
=2*22/7*10.5
=21*22/7
=3*22
=66CM
= 0.66M
Time taken to complete 1 revolution=60Sec
Speed=distance/time
=0.66/60
=0.011 m/s
Given: time taken, t = 60 s
the radius of the dial of the clock, r = 10.5cm
To Find: speed of the tip of the second hand of the clock, s.
Solution:
To calculate s, the formula used:
- speed = distance / time
- s = d /t
Applying the above formula:
s = d / 60 ⇒1
here, d = circumference of the dial of the clock
d = 2πr ⇒2
here, π = 3.15
r = 10.5cm
First, convert 10.5cm into m:
1 m = 100cm
100cm = 1m
10.5cm = (1/100) x 10.5
= 10.5 / 100
= 0.105 m
Putting he above value in equation 2:
d = 2x 3.15 x 0.105
= 6.3 x 0.105
= 0.66 m
Putting the value of d in equation 1:
s = 0.66 / 60
= 66 / (60 x 100)
= 66 / 6 x1000
= 11 / 1000
= 0.011
s = 0.011 m/s
Hence, the speed of the tip of the second hand of the clock is 0.011 m/s.