Question

the top ladder of length 15 m reaches a window 9 m above the ground. what is the distance between the base of the wall and that of the ladder​

Answer 1

Answer:

12 m

Step-by-step explanation:

.Hence, the ladder leaning against the wall forms a right-angled triangle. In ∆ABC,

∠B = 90° According to Pythagoras’ theorem, l(AC)2 = l(AB)2 + l(BC)2

∴ 152 = l(BC)2 + 92

∴ 225 = l(BC)2 + 81

∴ 225 – 81 = l(BC)2

∴ 144 = l(BC)2

∴ 122 = l(BC)2

∴ l(BC) = 12

∴ The distance between the base of the wall and that of the ladder is 12 m.