Question

The top of a broken tree touches the ground at a distance of 12 m from its base. If the tree is broken at a height of 5 m from the ground then find the actual height of the tree.    ( Also draw the figure)​

Answer 1

Answer:

hiiii

Step-by-step explanation:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.

Answer 2

Answer:

18m

Step-by-step explanation:

Let A'CB represent the tree before it is broken at the point C and let the top A' touches the ground at A after it broke Then Triangle ABC is the right angled triangle, right angled at B.

Then, AB = 12m and BC = 5m

Using Pythagoras Theorem in Triangle ABC,

(AC)² = (AB)² + BC²

(AC)² = 12² +5²

(AC)² = 144 + 25

(AC)² = 169

AC =√169

AC = 13m

Actual height of tree= 5+13= 18m

Hope it helps you...

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