Question

The top of a ladder of length 15 m reaches a window 9 m above the ground. What is the distance between the base of the wall and that of the ladder?

Answer 1

Answer:12

Step-by-step explanation:

Hypotenuse=15

Opposite side=9

Apply Pythagoras theorem

(15)sq=(9)sq+(x)square

(X)sq=144

X=12

Answer 2

Step-by-step explanation:

AnswEr:

Distance between the base of the wall and ladder is 12m.

Step By Step Explanation:-

$\large\bold{\underline{\sf{\red{\:\:Given\:\:-}}}}$

Length of the ladder = 15 m

Distance = 9 m

$\dag\:\:\small\bold{\underline{\sf{\red{Now,\:By\: Using\: Pythagoras\: Theorem}}}}$

$\longrightarrow\sf\: (Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2$

$\longrightarrow\sf\: Hypotenuse = 15$

$\longrightarrow\sf\: Base = 9$

Now,

$\longrightarrow\sf\: (15)^2 = (9)^2 + (P)^2$

$\longrightarrow\sf\: 225 - 81 = P^2$

$\longrightarrow\sf\: 144 = P^2$

$\longrightarrow\sf\: \sqrt{144} = P^2$

$\longrightarrow\large{\underline{\boxed{\sf{\blue{P \:=\: 12}}}}}$

Hence, Distance between foot of ladder and base of wall is 12 m.

$\rule{150}2$