Question

The top of a table is in
the shape of a parallel gram.
It base is 8cm and

altitude is 3cm. Find the cost
as painting the table top
at the rate of 35perm²​

Answer 1

$\huge\mathbb{\underline{SOLUTION:-}}$

$\bold{given:-}\begin{cases}\sf{base\:of\: parallelogram=8cm}\\ \sf{altitude\:of\: parallelogram=3cm}\end{cases}$

• Find the area of parallelogram

• then find the cost of painting

$\boxed{\sf{\red{Area\:of\: parallelogram=base\times height}}}$

$\bf\underline{\underline{According\:To\:question:-}}$

$\sf\implies Area=8cm\times 3cm\\ \\ \sf\implies Area=24cm{}^{2}$

• The area of parallelogram or table top is 24 square cm

$\boxed{\sf{Cost\:of\: painting=35per \:m{}^{2}}}$

$\sf\implies Cost\:of\: painting=24\times 35\\ \\ \sf\implies Cost\:of\: painting=840Rs.$

$\boxed{\sf{\purple{Cost\:of\: painting=840Rs.}}}$

#BAL

#answerwithquality

Answer 2

$\underline \mathbb{SOLUTION}$

$\underline \mathbb{GIVEN}$

》Base of parallelogram = 8 cm

》Altitude of parallelogram = 3 cm

$\underline \mathbb{TO\:FIND}$

》Area of parallelogram

》And cost of painting

AREA OF PARALLELOGRAM = BASE × HEIGHT

$\underline \mathbb{ATQ}$

》Area = 8cm × 3cm

$= > area = 24 {cm}^{2}$

$= > area \: of \: parallelogram = 24 {cm}^{2}$

$\underline \mathbb{GIVEN}$

$cost \: of \: painting = 35 {m}^{2}$

$= > cost \: of \: painting = 24 \times 35$

$= > cost = 840rs.$

$\underline \mathbb{HENCE}$

》COST OF PAINTING IS 840 Rs.

_______________________________________

#BAL

#Answerwithquality