Question

The top of two poles of height 20m and 14m are connected by a wire . If the wire makes angle of 30 with horizontal , then the length of the wire is?????

Answer 1

Here is the solution

Answer 2

Answer:

11.998 m

Step-by-step explanation:

Height of two poles i.e. AB and CE are 14 m and 20 m

DE = CE - CD = 20-14 = 6 m

Length of wire is AE

IN ΔADE

$tan \theta = \frac{Perpendicular}{Base}$

$tan 30^{\circ} = \frac{DE}{AD}$

$\frac{1}{\sqrt{3}}= \frac{6}{AD}$

$AD=6\sqrt{3}=10.39$

IN ΔADE

$Hypotenuse^2=Perpendicular^2+base^2$

$AE^2=DE^2+AD^2$

$AE=\sqrt{DE^2+AD^2}$

$AE=\sqrt{6^2+10.39^2}$

$AE=11.998$

Hence the length of the wire is 11.998 m