The tops of two poles of height 18 m and 12 m are connected by a wire. If the wire makes an angle of measure 30 with horizontal, then the length of the wire is .....,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) 12 m
(b) 10 m
(c) 8 m
(d) 4 m
Answers
Answered by
38
According to the problem given ,
Height of the first pole = AB = 18 m
Height of the second pole = CD = 12 m
Length of the wire = AD
AE = AB - BE
= AB - CD
= 18 - 12
AE = 6 m
In ∆ AED ,
< AED = 90° ,
<ADE = 30° ( given )
Sin 30° = AE/AD
1/2 = 6/AD
AD = 6 × 2
AD = 12 m
Therefore ,
Length of the wire = AD = 12 m
Option ( a ) is correct.
I hope this helps you.
: )
Height of the first pole = AB = 18 m
Height of the second pole = CD = 12 m
Length of the wire = AD
AE = AB - BE
= AB - CD
= 18 - 12
AE = 6 m
In ∆ AED ,
< AED = 90° ,
<ADE = 30° ( given )
Sin 30° = AE/AD
1/2 = 6/AD
AD = 6 × 2
AD = 12 m
Therefore ,
Length of the wire = AD = 12 m
Option ( a ) is correct.
I hope this helps you.
: )
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Answered by
18
Option A is correct.
Let the legth of wire is AC.
We know the angle which is 30°.
Length of BC = height of begger pole - height of smaller pole
= 18-12
= 6 meter
Now, applying sin rule in ΔABC as shown in figure.
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