The torque of the force F =(2i -3j+4k)N acting at the point r =(3i +2j+3k)
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Ans. A = 3i + 4j - 4k B = - i + 2j + 6k 0= 137° 36' 2.10 Prove the law of cosines for ... j + k) m2 2.22 A force F = (4i - 5j + 2k) N is acting at the point r = (3i + 2j - k) m
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Explanation:
torque=force ×r...................
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