the torque of the force F=(3i+3j+3k)n acting at the point r=(3i+2j+3k)m about the origin be
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T= r× F
T= (3i^+2j^+3k^)× (3i^+3j^+3k^)
With the help of cross product rule,
T= (6-9)i^-(9-9)j^+ (9-6)k^
T= -3i^+3k^
T= (3i^+2j^+3k^)× (3i^+3j^+3k^)
With the help of cross product rule,
T= (6-9)i^-(9-9)j^+ (9-6)k^
T= -3i^+3k^
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