Physics, asked by narayannirguda, 4 months ago

the torque transmitted by a solid shaft of diameter 40mm if the shear stress is not to exceed 4MP a would be​

Answers

Answered by BlossomingBud123
0

Answer:

Answer:

1. Inside buildings. You might have noticed that large office buildings, stores, hospitals, and other many other buildings have convex mirrors in the corners.

2. Sunglasses. We might have used sunglasses many times.

3. Vehicle mirrors.

4. Magnifying glasses.

5. For security purposes.

6. Street light reflectors.

Hope it would help you....

Answered by sadiaanam
0


The torque transmitted by a solid shaft of diameter 40mm if the shear stress is not to exceed 4MP a would be​

To determine the torque that can be transmitted by a solid shaft of diameter 40mm with a maximum shear stress of 4 MPa, we need to use the formula for torsional stress:

τ = T / J

where:
τ = shear stress (MPa)
T = torque (Nm)
J = polar moment of inertia (mm^4)

The polar moment of inertia can be calculated as:

J = (π/32) * d^4

where d is the diameter of the shaft.

Substituting the values, we get:

J = (π/32) * (40mm)^4 = 31,415 mm^4

And using the formula for torsional stress, we can solve for T:

T = τ * J = 4 MPa * 31,415 mm^4 = 126,460 Nm

So, the maximum torque that can be transmitted by a solid shaft of diameter 40mm with a maximum shear stress of 4 MPa would be 126,460 Nm.

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